How Do You Find Distance if You Know Acceleration Initial Velocity and Time

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Velocity is a function of time and defined by both a magnitude and a direction. ^[1] Often in physics problems, you will need to calculate the initial velocity (speed and management) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the data given in a problem, you can determine the proper equation to use and easily answer your question.

1. 1

   Know the right equation to utilise. In order to solve whatsoever physics problem you lot must know which equation to utilize. Writing down all of the known information is the first pace to finding the right equation. If you have values for the final velocity, acceleration, and time involved, you can use the following equation:

   • Initial velocity: Five_i = Five_f - (a * t)
   • Understand what each symbol stands for.
     • V_i stands for "initial velocity"
     • V_f stands for "concluding velocity"
     • a stands for "acceleration"
     • t stands for "time"
   • Note that this equation is the standard equation used when finding initial velocity.

2. 2

   Fill in the known information. Once you have written the known information and determined the proper equation, you tin can fill in values for the appropriate variables. Advisedly setting up each problem and writing out every stride of the process is of import.

   • If you make a fault, y'all can hands detect it by looking back at all of your previous steps.

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3. iii

   Solve the equation. With all of the numbers in place, utilize the proper order of operations to finish the problem. If you're allowed, employ a estimator to limit the number of simple math mistakes.

   • For case: An object accelerating east at 10 meters (32.eight ft) per second squared traveled for 12 seconds reaching a final velocity of 200 meters (656.2 ft) per second. Detect the initial velocity of that object.
     • Write the known information:
     • V_i = ?, V_f = 200 chiliad/s, a = 10 m/s^two, t = 12 s
   • Multiply the acceleration and fourth dimension. a * t = 10 * 12 =120
   • Subtract the production from the last velocity. V_i = V_f – (a * t) = 200 – 120 = 80 V_i = 80 m/south east
   • Write your answer correctly. Include a unit, commonly meters per second or grand/south, as well as a direction the object was traveling in. Without providing data nigh the direction, you only have a measurement of speed rather than velocity.

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1. one

   Know the right equation to use. In lodge to solve any physics trouble you lot must know which equation to use. Writing down all of the known information is the beginning step to finding the right equation. If y'all know values for the altitude, fourth dimension, and acceleration, you lot tin can use the following equation:

   • Initial velocity: 5_i = (d / t) - [(a * t) / 2]
   • Understand what each symbol stands for.
     • V_i stands for "initial velocity"
     • d stands for "altitude"
     • a stands for "dispatch"
     • t stands for "time"

2. ii

   Fill up in the known information. Once you take written the known information and adamant the proper equation, y'all can fill in values for the appropriate variables. Carefully setting upward each problem and writing out every step of the process is important.

   • If you make a mistake, you can easily detect it by looking back at all of your previous steps.

3. 3

   Solve the equation. With all of the numbers in place, apply the proper order of operations to finish the trouble. If you're allowed, use a calculator to limit the number of simple math mistakes.

   • For example: An object accelerating west at vii meters (23.0 ft) per second squared traveled a altitude of 150 meters (492.1 ft) within xxx seconds. Summate the initial velocity of that object.
     • Write the known information:
     • V_i = ?, d = 150 chiliad, a = seven m/s², t = xxx s
   • Multiply the acceleration and fourth dimension. a * t = 7 * 30 = 210
   • Divide the product by two. (a * t) / 2 = 210 / 2 = 105
   • Divide the distance by the time. d / t = 150 / 30 = five
   • Decrease your start caliber from the second quotient. V_i = (d / t) - [(a * t) / 2] = 5 – 105 = -100 V_i = -100 grand/southward west
   • Write your answer correctly. Include a unit of measurement, usually meters per second or thou/due south, every bit well as a direction the object was traveling in. Without providing data well-nigh the direction, yous just have a measurement of speed rather than velocity.

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1. ane

   Know the right equation to use. In society to solve any physics trouble you lot must know which equation to utilize. Writing downwardly all of the known information is the beginning step to finding the correct equation. If you are given the final velocity, dispatch, and distance, you can use the post-obit equation:

   • Initial velocity: 5_i = √ [V_f ² - (2 * a * d)]
   • Empathise what each symbol stands for.
     • V_i stands for "initial velocity"
     • V_f stands for "final velocity"
     • a stands for "dispatch"
     • d stands for "distance"

2. 2

   Fill in the known data. One time you have written the known information and determined the proper equation, y'all tin can fill in values for the appropriate variables. Carefully setting upwardly each problem and writing out every footstep of the process is important.

   • If you lot brand a mistake, yous can hands find it past looking back at all of your previous steps.

3. 3

   Solve the equation. With all of the numbers in identify, use the proper order of operations to stop the problem. If you're immune, use a calculator to limit the number of simple math mistakes.

   • For instance: An object accelerating northward at v meters (sixteen.four ft) per 2nd squared traveled 10 meters (32.8 ft), catastrophe upward at a final velocity of 12 meters (39.four ft) per second. Calculate the object's initial velocity.
     • Write the known information:
     • 5_i = ?, V_f = 12 m/s, a = 5 thou/sⁱⁱ, d = x m
   • Square the final velocity. 5_f ⁱⁱ = 12² = 144
   • Multiply the acceleration by the altitude and the number two. 2 * a * d = 2 * v * 10 = 100
   • Subtract this product from your previous one. V_f ² - (two * a * d) = 144 – 100 = 44
   • Take the foursquare root of your answer. = √ [Five_f ² - (ii * a * d)] = √44 = 6.633 Five_i = vi.633 m/s north
   • Write your answer correctly. Include a unit of measurement of measurement, usually meters per 2nd or grand/s, likewise as a direction the object was traveling in. Without providing data nigh the direction, y'all merely have a measurement of speed rather than velocity.

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1. 1

   Know the correct equation to use. In order to solve any physics trouble you must know which equation to use. Writing down all of the known information is the showtime step to finding the right equation. If you lot are given the terminal velocity, time, and distance, you can apply the following equation:

   • Initial velocity: Five_i = ii(d/t) - V_f
   • Understand what each symbol stands for.
     • 5_i stands for "initial velocity"
     • Five_f stands for "final velocity"
     • t stands for "time"
     • d stands for "distance"

2. 2

   Fill in the known information. In one case yous take written the known information and determined the proper equation, you can fill up in values for the appropriate variables. Carefully setting upward each problem and writing out every step of the process is of import.

   • If you brand a fault, you tin can easily find it by looking back at all of your previous steps.

3. 3

   Solve the equation. With all of the numbers in place, utilise the proper order of operations to end the trouble. If you're allowed, use a calculator to limit the number of unproblematic math mistakes.

   • For case: An object with a last velocity of 3 meters (nine.viii ft) traveled south for 15 seconds and covered a distance of 45 meters (147.six ft). Calculate the object'due south initial velocity.
     • Write the known information:
     • 5_i = ?, 5_f = three m/s, t = 15 s, d = 45 m
   • Split up distance by time. (d/t) = (45/fifteen) = iii
   • Multiply that value by 2. ii (d/t) = two (45/fifteen) = half-dozen
   • Subtract final velocity from the product. 2(d/t) - 5_f = 6 - 3 = three V_i = 3 m/s due south
   • Write your answer correctly. Include a unit of measurement, usually meters per 2nd or 1000/s, too as a direction the object was traveling in. Without providing information nearly the direction, you only accept a measurement of speed rather than velocity.

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Add New Question

• Question

  A bullet of lx gm is fired using a rifle of mass 12kg. Burglarize recoils with a velocity of ii.5m/s. What is the initial velocity?

  

  Kinetic energy -> Kinetic energy 0.5mv^2 -> 0.5mv^2 0.5 x 12 ten 2,5^2 = 0.5 x 0.06 x v^2 6 ten 6.25 = 0.03 10 v^2 37.5 = 0.03 x v^2 sqrt(37.5/0.03) = five sqrt(1250) = five v = 35.3 1000/s

• Question

  If deportation and time are related as s = 3.5t + 5t2, what is the initial velocity?

  

  Initial velocity is 3.5. The equation is southward = ut + 1/2at^2, where southward - distance, u - inititial velocity, and a - acceleration.

• Question

  How practice I modify the dispatch formula to one that gives me initial velocity?

  

  You lot can't modify the dispatch formula to one that gives you the initial velocity you lot want, as a=five/t. However, Vf=Vi+a.t is re-arranged. 6=Vf-a.t, a=Vf-Vi/t, t=Vf-Vi/a.

• Question

  How do I find acceleration?

  

  Subtract the initial velocity from the final velocity, then separate the issue past the fourth dimension interval.

• Question

  A ball is thrown upward at an bending of 30 with the horizontal, and lands on the top edge of a building that is twenty meters abroad. With the top border existence 5 meters above the throwing point, what is the initial speed of the brawl in meters/second?

  

  Assuming you are not including air resistance (which would make this trouble far more difficult), the kinematic equations would be the usual southward= (a/2)t^ii+ vt+ d, where a is the dispatch vector, v is the initial velocity vector, and d is the initial position vector. Separating x (horizontal) and y (vertical) components and taking the initial speed to be "v" and the intial position to be d= (0, 0), we have x= v cos(30)t=(\sqrt{iii}/2)v t and y= (-g/2)t^3+ five sin(xxx)= -4.9t^2+ (0.five)vt where v is the initial speed. Since the brawl is to end upwards "20 meters abroad, the top border is 5 meters in a higher place the throwing point", x= 20 and y= five. Solve the two equations (\sqrt{3}/2)v t = twenty and -iv.9t^two+

• Question

  How would I find final velocity?

  

  As soon as you lot stop, the final velocity is zero. Then, simply count backward to the start and divide by pieRx3.

• Question

  A race car starts at rest and speeds upwards uniformly to the right until it reaches a maximum velocity of 60m/south in xv sec. How exercise I calculate the dispatch?

  

  Cabbache

  Community Answer

  The acceleration is how much the velocity of the auto changes every second. If the velocity increased by 60 in fifteen seconds, and then in a second it would accept increased past 4m/south.

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Article Summary X

To discover initial velocity, beginning by multiplying the acceleration by the time. Then, divide that number past 2 and write down the caliber you get. Next, carve up the distance by the time and write down that quotient as well. Finally, subtract your first quotient from your 2nd quotient to notice the initial velocity. To learn how to find initial velocity using the concluding velocity, continue reading!

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Source: https://www.wikihow.com/Find-Initial-Velocity

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